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AKRON, Ohio – After a nine-day break from competition The University of Akron women's tennis team returns to the court on Thursday when it plays host to Youngstown State at 12:30 p.m. ET at LaTuchie Tennis Center in nearby Stow (driving directions).
The Zips (7-6), who have won six of their last seven matches, last competed on Feb. 24 when they lost 6-1 at then 52nd-ranked Columbia as part of a three-match East Coast road trip. The away swing included a 7-0 win over Wagner (Feb. 22) on a neutral court and a 5-2 victory at New Jersey Institute of Technology (NJIT) (Feb. 23). Columbia was UA's seventh nationally-ranked opponent this season.
Akron's No. 1 doubles team of Prang Pantusart and Angelina Jogasuria is ranked 55th nationally and owns an 10-0 record this season. Jogasuria also plays at No. 1 singles and is 5-1 this year when competing in that flight.
Youngstown State (6-3) enters the contest looking to rebound from a 7-0 loss at No. 55 Ohio State on Sunday that ended a six-match win streak.
UA owns a 22-3 advantage in the all-time series with YSU and has won six-straight meetings, including a 7-0 victory in Akron on Feb. 12, 2012. This is the seventh-straight year the programs have competed against one another.
The two-time defending Mid-American Conference champions, Akron opens league play at home on March 22 versus Northern Illinois at 1 p.m. The Zips face Oakland in a non-conference match that day at 6 p.m., and take on non-league foe Cleveland State on March 23 at 5 p.m.